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5/9x^2=125
We move all terms to the left:
5/9x^2-(125)=0
Domain of the equation: 9x^2!=0We multiply all the terms by the denominator
x^2!=0/9
x^2!=√0
x!=0
x∈R
-125*9x^2+5=0
Wy multiply elements
-1125x^2+5=0
a = -1125; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-1125)·5
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*-1125}=\frac{-150}{-2250} =1/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*-1125}=\frac{150}{-2250} =-1/15 $
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